This task is quite simple in fact. The truth tables shows the relationship between the two and only when they are true. The only way the out come can be true is if the two are the same. For example, if both were false then it would be true and if both were false than it would be true. Any other time when you have True/False or False/True, that is when it is False. Here is a screen shot of both elements being True that yield a True.
Task 3
When running through all of the combinations every the first three were True while the last one was False because both of the inputs were true. This does indeed prove De Morgan's Law. It is the exact same thing, just moved in or out of the parentheses. You just have to make sure that you distribute all of the signs. Here is a screen shot of this.
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